3. E. Yu. K.  =120 V, R3=20 Ω, R4=25 Ω, R1 qarshilikda kuchlanish tushuvi U1=40V. Ampermetr I=2A tokni ko‘rsatmoqda. R2 qarshilik aniqlansin

3. E.Yu.K.  =120 V, R3=20 Ω, R4=25 Ω, R1 qarshilikda kuchlanish tushuvi U1=40V. Ampermetr I=2A tokni ko‘rsatmoqda. R2 qarshilik aniqlansin.

Berilgan	formula	hisoblash
.  =120 V, R3=20 Ω, R4=25 Ω, IA=2A U1=40V R2=?	I2+I3=IA U1=I1R1 Ru=(R2*R3/R2+R3)+R1+R4 R1=U1/I1	R1=40/2=20Ω +20+25= 5R2=300Ω R2=60Ω

4. Agarda 20 - rasmdagi qarshiliklar R1=3 Ω, R2=2 Ω, R3=7.5 Ω, R4=2Ω, R5=5 Ω, R6=10 Ω
bo‘lsa, va zanjirning AB qismidagi kuchlanish Ua=100V bo‘lsa, har bir o‘tkazgichdan o‘tayotgan tok kuchi topilsin.

Berilgan	Formula	Yechish
R1=3 Ω, R2=2 Ω, R3=7.5 Ω, R4=2Ω, R5=5 Ω, R6=10 Ω Ua=100V I1 = I2= I3=I=?	R1,2= = + + I1=I2=I3=I4=I5=I6=I I=U*R	R1,2=6/5 1/R4,5,6=1/2+1/5+1/10 R4,5,6=5/4 R=5/4+15/2+6/5=199/20 I=