(or any equivalent fraction).
The textbook costs
of Devora’s
money. The notebook costs
of that amount,
or
of Devora’s
money. Thus, Devora has spent
of her money.
Subtract from 1 to get the fraction she has left:
.
Alternatively, pick a value for Devora’s money. (Look at the denominators in
the problem—4 and 6—and pick a value that both numbers go into evenly.)
For instance, say Devora has $120. She would spend
, or $30, on the
textbook. She would spend
of that
amount, or $5, on the notebook. She
would have spent $35 and would have $85 left, and thus
of her money
left. Reduce
to get
, or enter
in the boxes.
4.
0.3482 × 10
–2
, 34.82 × 10
–4
, and 3,482 × 10
–6
only.
Note that the first
answer is negative, so it cannot be correct. For the second answer, move the
decimal 2 places to the left: 0.3482 × 10
–2
= 0.003482 (correct). For the third
answer, move the decimal 4 places to the
right
(since the exponent is positive)
—this move makes the number much greater and cannot be correct. For the
fourth answer, move the decimal 4 places to the left: 34.82 × 10
–4
= 0.003482
(correct). For the fifth answer, move the decimal 6 places to the left: 3,482 ×
10
–6
= 0.003482 (correct).
5.
0.00001212 × 10
3
only.
First, simplify 12.12 × 10
–3
= 0.01212. Now, test
which answers are equal to this value. The first answer is negative, so it
cannot be correct. The second answer is 0.012 and is therefore incorrect (the
end has been “chopped off,” so the number is not the same value). The third
answer is 0.00001212 × 10
3
= 0.01212 and is correct. The fourth answer is
0.01212 × 10
3
= 12.12 and is not correct.
6.
(A).
Translate the words into math. If
x
means “how many,” then “how
many fifths” is
:
5 =
× 10
5 =
25 = 10
x
=
x
x
= 2.5
7.
(A).
Simplify each quantity by breaking down to primes and canceling
factors:
Quantity A:
Quantity B:
Since
, Quantity A is greater. You can compare these fractions by
making a common denominator, by cross-multiplying, or by comparing the
decimal equivalents 0.333 (repeating infinitely) and 0.3.
If there are identical factors in each quantity in the same position (e.g., 3
2
on
top or 4
2
on bottom), then you can save time by canceling those factors first
from both quantities.
8.
(D).
This question is
not
asking for
of
. Rather,
and
are
fractions of the same number (the number of students in the whole class). A
good way to avoid this confusion is to plug in a number for the class. Pick 12,
as it is divisible by both 4 and 12 (the denominators of the given fractions).
Class = 12
Girls = 5
Girls who take Spanish = 3 (which is
of all the students in the class)
The question asks for the number of girls who take Spanish over the number
of girls. Thus, the answer is
.
9.
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