Correct Answer: C
QUESTION 46
What is a function of spine-and-leaf architecture?
mitigates oversubscription by adding a layer of leaf switches
limits payload size of traffic within the leaf layer
offers predictable latency of the traffic path between end devices
exclusively sends multicast traffic between servers that are directly connected to the spine
Correct Answer: C
QUESTION 47
What differentiates device management enabled by Cisco DNA Center from traditional campus device management?
CLI-oriented device
centralized
per-device
device-by-device hands-on
Correct Answer: B
QUESTION 48
Refer to the exhibit.
Router R1 is added to the network and configured with the 10.0.0.64/26 and 10.0.20.0/24 subnets. However, traffic destined for the LAN on R3 is not accessible. Which command when executed on R1 defines a static route to reach the R3 LAN?
A. ip route 10.0.15.0 255.255.255.0 10.0.20.1
B. ip route 10.0.15.0 255.255.255.192 10.0.20.1
C. ip route 10.0.0.64 255.255.255.192 10.0.20.3
D. ip route 10.0.15.0 255.255.255.0 10.0.20.3
Correct Answer: D
QUESTION 49
Refer to the exhibit.
Router1#show ip route
Gateway of last resort is 10.10.11.2 to network 0.0.0.0
209.165.200.0/27 is sudnetted, 1 subnets
B 209.165.200.224 [20/0] via 10.10.12.2, 03:03:03
209.165.201.0/27 is sudnetted, 1 subnets
B 209.165.201.0 [20/0] via 10.10.12.2, 03:03:03
209.165.202.0/27 is subnetted, 1 subnets
B 209.165.202.128 [20/0] via 10.10.12.2, 03:03:03
10.0.0.0/8 is variably subnetted, 8 subnets, 4 masks
C 10.10.10.0/28 is directly connected, GigabitEthernet0/0 C 10.10.11.0/30 is directly connected, FastEthernet2/0
C 10.10.12.0/30 is directly connected, GigabitEthernet0/1
O 10.10.13.0/25 [110/2] via 10.10.10.1, 00:00:03, GigabitEthernet0/0
O 10.10.13.128/28 [110/2] via 10.10.10.1, 00:00:03, GigabitEthernet0/0 O 10.10.13.144/28 [110/2] via 10.10.10.1, 00:00:03, GigabitEthernet0/0 O 10.10.13.160/29 [110/2] via 10.10.10.1, 00:00:03, GigabitEthernet0/0 O 10.10.13.208/29 [110/2] via 10.10.10.1, 00:00:03, GigabitEthernet0/0 S* 0.0.0.0/0 [1/0] via 10.10.11.2
Drag and drop the prefix lengths from the left onto the corresponding prefixes on the right. Not all prefixes are used.
A. 10.10.13.0 – 255.255.255.128
10.10.13.144 – 255.255.255.240
10.10.13.160 – 255.255.255.248
209.165.202.128 – 255.255.255.224
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