Choice B is correct. The x-coordinates of the x-intercepts of the
graph are –3, 0, and 2. This means that if y = f (x) is the equation of
the graph, where f is a polynomial function, then (x + 3), x, and (x − 2)
are factors of f. Of the choices given, A and B have the correct factors.
However, in choice A, x is raised to the first power, and in choice B,
x is raised to the second power. At x = 0, the graph touches the x-axis
but doesn’t cross it. This means that x, as a factor of f, is raised
to an even power. If x were raised to an odd power, then the graph
would cross the x-axis. Alternatively, in choice A, f is a third-degree
polynomial, and in choice B, f is a fourth-degree polynomial. The
y-coordinates of points on the graph become large and positive as x becomes large and negative; this is consistent with a fourth-degree
polynomial, but not with a third-degree polynomial. Therefore, of the
choices given, only choice B could be the equation of the graph.
Choice A is incorrect. The graph of the equation in this answer choice
has the correct factors. However, at x = 0 the graph of the equation in
this choice crosses the x-axis; the graph shown touches the x-axis but
doesn’t cross it. Choices C and D are incorrect and are likely the result
of misinterpreting the relationship between the x-intercepts of a graph
of a polynomial function and the factors of the polynomial expression.
QUESTION 12
Choice D is correct. Dividing both sides of equation
2a _
b = 1
_
2 by 2
gives a _
b = 1
_
4 . Taking the reciprocal of both sides yields b _
a = 4.
Choice A is incorrect. This is the value of a _
2b , not b _
a . Choice B is
incorrect. This is the value of a _
b , not b _
a . Choice C is incorrect. This is
the value of b _
2a , not b _
a .
ANSwER ExPlANATIONS
| SAT Practice Test #8 QUESTION 13