A) 960 B) 640 C) 1280 D) 1600
Ishlanishi: 1) DNK dagi jami S ni topamiz: har doim A miqdori T ga, G
miqdori S ga teng.
6400 --- 100%
x(S) --- 25% x=(6400*25)/100 x=1600
S=1600 A-1600-25%=25%-1600-T ni tashkil qiladi => A=T=G=S
2) Jami T dan 2-ipdagi T ni topamiz:
1600 --- 100%
x --- 60% x=(1600*60)/100 x=960 T=960
3)
2-ipdagi T 1-ipdagi A ga teng va A dan i-RNK dagi U
sintezlanadi. Bu T=A=
U degani:
i-RNK 1-ipdan sintezlangan DNK da -
T SGA 2-ip
A GST 1-ip
i-RNK da -
U SGA
U=960; Javob: A ____________________________
51. DNK molekulasini ikki ipida 25600 ta nukleotid bor.
Umumiy nukleoitlarni 25 % i sitozin. 2-ipda timin nukleotidini 45 %
i, guaninlarni esa 55 % joylashgan. DNK ning 1-ipidan sintezlangan
i-RNK ni uzunligini toping
A) 43520 B) 21,760 C) 72,5 D) 10,88
Ishlanishi: 1) 25600 --- 100%
x(S) --- 25% x=(25600*25)/100 x=6400 S=6400
2) A-6400-25%=25%-6400-T ni tashkil qiladi => A=T=G=S
3) Jami G(A,S,T) ni 55% ini topamiz:
6400 --- 100%
x --- 55% x=(6400*55)/100 x=3520 G=3520
6400-3520=2880 Jami G(A,S,T) ni 45% i=2880
4) 2-ipda: T=2880, A=3520, S=2880; G=3520;
1-ipda: A=2880, T=3520, G=2880, S=3520; i-RNK: U=2880, A=3520, S=2880, G=3520 .
i-RNK 1-ipdan sintezlangan
5) Nukleotidlar orasidagi masofa-0,34 nm yoki 3,4 A
0
L=(U+S+G+A)* 0,34 nm=12800*0,34 nm=
4352 nm Javob: A ____________________________
52. Uzunligi 216,24 nm bo’lgan DNK bo’lagidan sintezlangan
mioglobin oqsilini og’irligi necha Dalton bo'ladi. (har bir nukleotid
345, aminokislota 120 Dalton deb olinsin).
