C) 250 D) 251
Ishlanishi: 1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N
2) i-RNK 126 ta nukleotid, DNK da 2 ta zanjirda :
126*2=252N
3) F=N-2 F=252-2=
250 Javob: C ____________________________
75. DNK molekulasining uzunligi 42,84 nm. Shu DNK
mutatsiyaga uchrab 6 juft nukleotidini yo’qotdi. Ushbu molekula
asosida sintezlangan oqsil tarkibidagi aminokislotalar sonini
aniqlang.
A) 40 B) 38 C) 42 D) 36
Ishlanishi: 1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N
2) i-RNK
126 ta nukleotid bo’ladi. 126-6=
120N Shunga ko’ra,
bu nukleotidlar nechta aminokislotani kodlashini topamiz :
3) AK=N/3 AK=120N/3=
40AK Javob: A ____________________________
76. DNK molekulasining uzunligi 42,84 nm. Shu DNK
mutatsiyaga uchrab 12 juft nukleotidini yo’qotdi. Ushbu molekula
asosida sintezlangan oqsil tarkibidagi aminokislotalar sonini
aniqlang.
A) 40
B) 38 C) 36 D) 34
Ishlanishi: 1) L=N*0,34 => N=L/0,34 N=42,84nm/0,34nm=126N
2) i-RNK
126 ta nukleotid bo’ladi. 126-12=
114N Shunga ko’ra,
bu nukleotidlar nechta aminokislotani kodlashini topamiz :
3) AK=N/3 AK=114N/3=
38AK Javob: B ____________________________
77. Nuklein kislotalar molekulasida nukleotidlar o'zaro
fosfodiefir bog'lari orqali bog'lanadi. DNK molekulasida 598 ta
fosfodiefir bog‘i bo‘lsa va undagi adenin nukleotidi umumiy
nukleotidlarni 20% tashkil etsa, ushbu DNK molekulasidagi guanin
va uratsil nukleotidlarini sonini aniqlang?
A) 120;180 B) 180;120 C) 118;0
D) 180;0 Ishlanishi: 1) 598+2=600N DNK dagi barcha N lar
2) 600---100%
x---20% x=(600*20)/100=120 A=120
3) 600---100%
x---30% x=(600*30)/100=180
