Tajriba ish №2 Mavzu: Massivlardan foydalanib dasturlash Ishdan maqsad

int a[][] = new int[n][m];
Quyidagi dasturda matritsa elementlarini kiritish, chiqarish va yig’indisini xisoblash amalga oshirilgan.


import java.util.Scanner;


public class Misol3 {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int n,m;
n = sc.nextInt();
m = sc.nextInt();
int a[][] = newint[n][m];
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
a[i][j] = sc.nextInt();
}
}
//matritsanichiqarish
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
System.out.print(a[i][j]+" ");
}
System.out.println("");
}
int s = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
s += a[i][j];
}
}
System.out.println("mtritsa elementlari yig`indisi "+s);
}
}




Topshiriqlar.
1-topshiriq:

1. 
   Bir o`lchamli sonli massivni o`rtacha qiymatidandan kichik elеmеntlarini o`rtacha qiymati хisоblansin.
   
2. 
   import java.util.Scanner;
   
3. 
   public class d_lab2 {
   
4. 
   public static void main(String[] args) {
   
5. 
   try (Scanner sc = new Scanner(System.in)) {
   
6. 
   System.out.print("Massivning uzunligi:");
   
7. 
   int n = sc.nextInt();
   
8. 
   int arr[] = new int[n];
   
9. 
   
10. 
    for (int i = 0; i < n; i++) {
    
11. 
    arr[i] = sc.nextInt();
    
12. 
    }
    
13. 
    int s = 0;
    
14. 
    int p = 1;
    
15. 
    
16. 
    for (int i = 0; i < n; i++) {
    
17. 
    
18. 
    s += arr[i];
    
19. 
    
20. 
    }
    
21. 
    
22. 
    for (int i = 0; i < n; i++) {
    
23. 
    if ((i + 1) % 2 == 1) {
    
24. 
    p *= arr[i];
    
25. 
    
26. 
    } else {
    
27. 
    s += arr[i];
    
28. 
    }
    
29. 
    }
    
30. 
    System.out.println("Natija: " + 1.0 * p / s);
    
31. 
    }
    
32. 
    }
    
33. 
    }