1 a sonidan 2ta oldingi sonini qo’shganda a soni hosil bo’luvchi sonlar logikasini tuzing

1) a sonidan 2ta oldingi sonini qo’shganda a soni hosil bo’luvchi sonlar logikasini tuzing.
Maslan: 0,1,1,2,3,5,8,13…..
Kodi:
main(){
int n=100;
int first=0;
int second=1;
while(first<=n){
print(first);
int sum=first+second;
first=second;
second=sum;
}
}
2) Shunday archa yasaydigan logika tuzingki uning yulduzchalar qiymati soni berilishiga qarab archani katta-kichikligi o’zgarib borsin
Kodi:
import 'dart:math';
main(){
int n=5;
int i=1;

int rowNumber=(n/2).round();

int counter=1;

while(counter<=rowNumber){
String probel='';
int k=1;
while(k<=rowNumber-counter){
probel="$probel ";
k++;
}
int j=1;
String row="";
while(j<=i){
row="$row*";
j++;
}
print("$probel$row$probel");
i+=2;
counter++;
}
}
3) Berilgan sondi nechi xonadan iborat ekanligini sanab beruvchi logika tuzing. (while) bilan tuzing
Kodi:
import 'dart:math';
main(){
int n=54;
int i=0;
while(in~/=10;
i++;
}
print(i);
}
4) while yordamida birinchi 10 ta tub sonni chop eting:

Kodi:
import 'dart:math';

main(){
int ct=0,n=0,i=1,j=1;
while(n<10)
{
j=1;
ct=0;
while(j<=i)
{
if(i%j==0) {
ct++;}
j++;
}

if(ct==2)

{
print(i);
n++;
}
i++;
}
}

5)Palindromik bo'lgan birinchi 10 ta tub sonlarni chop eting

Kodi:
import 'dart:math';
main(){
int count = 0;

for (int i = 10; i <= 1000; i++) {

int num = i, revNum = 0;

while (num != 0) {
int digit = num % 10;
num ~/= 10;
revNum = revNum * 10 + digit;
}
if (revNum == i) {
bool isPrime = true;
for (int j = 2; j <= i / 2; j++) {

if (i % j == 0) {

isPrime = false;
break;
}

}
if (isPrime) {

print(i);
count++;
if (count == 10) {
count = 0;
}
}
}
}
}