Sinf Ismi, Familiyasi sana

Sinf _______ Ismi, Familiyasi _________________________ sana _____
5-sinf Matematikadan 2-BSB savollari
Demo variant
1.M5.SA.8 Ko‘paytmani hisoblang:

1. 
   607 35 = (2 ball)
   
2. 
   71 86= (1 ball)
   

2. M5.SA.8 Ko‘paytma ko‘rinishida yozing va hisoblang:

1. 
   65+65+65+65= (1 ball)
   
2. 
   y+y+y+y+y+y+y+y= (1 ball)
   

3. M5.SA.9 Bo‘lishni burchak usulidan foydalanib bajaring:

a) 9450 : 18= (2 ball)
b) 441 559 : 109 = (3 ball)

4. M5.SA.10 Tenglamani yeching:

a) 13 x = 208 (1 ball)
b) 555: x= 37 (1 ball)

5 . M5.SA.20 Masalani yeching:
Bog‘chaga mashinada 200 litr sut keltirildi. Sutni quyib olish uchun sig‘imi 32 litr bo‘lgan bidonlardan nechta kerak ? Oxirgi bidonga qancha sut quyiladi ?
(3 ball)

O‘quvchining to‘plagan balli: __________
Tekshiruvchi o‘qituvchi: ___________________ ___________ (imzo)

Baholash mezoni

№	Ball	Javob	Deskriptor
1	3	a) 21245 b)6106	1) a) uchun 607 35 faqat ko‘paytmani keltirsa, 1 ball; 2) 607 35 ko‘paytmani ustun shaklida to‘g‘ri topsa, 2 ball; 3) b) uchun 71 86 ko‘paytmani to‘g‘ri topsa, 1 ball; 4) ikkala misolni ham to‘g‘ri ishlasa jami 3 ball.
2	2	a)65 4=260 b)8y	Ko‘paytma ko‘rinishiga keltirib, uni xisoblay olsa, 1 balldan jami 2 ball
3	5	a)630 b)4051	a)Bo‘lishni burchak usulidan foydalanib bajara olsa 2 ball, ozgina kamchiligi bo‘lsa, 1 ball b) To‘g‘ri jvobga erishsa 3 ball, hisoblashda ozgina kamchilik bo‘lsa, 2 ball, burchak usulda yozsa, lekin qo‘pol hatoga yo‘l qo‘ysa, 1 ball
4	2	a)x=16 b)x=15	a)Noma’lum ko‘paytuvchini topa olsa 1ball b)Noma’lum bo‘luvchini topa olsa 1ball
5	3	7 ta bidon kerak 8 litr oxirgi bidonga	Masala yechishda 200 ni 32 ga bo‘lib, to‘liqsiz bo‘linmani topa olsa, 1 ball, qoldiqlini topib bo‘lish amalini to‘g‘ri bajarsa, 2 ball, Qoldiqni bilib, qolgan sutga ham bitta idish kerakligini bilsa, 3ball
Jami:	15