Berilgan funksiyalardan variant tanlanib, olingan variantlar ustida quyidagi amallar bajariladi

2-amaliy ish topshiriqlari: Matlab paketida signallarga spektral ishlov berish



Bu yerda:
x – 0 dan boshlab 0.1 qadam bilan berilgan oraliqgacha davom etadigan to’plam. Misol ucun (x=0:0.1: *N)
N – talabaning jurnaldagi raqami;


Berilgan funksiyalardan variant tanlanib, olingan variantlar ustida quyidagi amallar bajariladi:

1. 
   1-berilgan z(x) funksiya ustida spektral o‘zgartirish algoritmlari asosida to‘g‘ri va teskari o‘zgartirishni amalga oshirish, kiruvchi va chiquvchi signallarni taqqoslash.
   

Olingan natijalar va dastlabki natijalar bilan birgalikda grafik orqali ifodalanadi.
Izoh: N hamma uchun jurnaldagi tartib raqami. Berilgan oraliq intervallariga qattiy rioya qilinishi shart. Ishninh yakunida amaliy ish bo’yicha xulosalar keltirilishi kerak. Titul pastda keltirilgan.
Variantlar

№	z(x)	O‘zgartirish algoritmi	Interval
1.	z=cos(x/π)-2sin(πx)	Deskret Fure	x (0; π*N), Δx=0.01
2.	z=cos(x2/π)-sin(πx/2)	Deskret Cosinus	x (0; π *N), Δx=0.01
3.	z=cos(xπ)+2sin(x)	Deskret Fure	x (0; 9/π *N, Δx=0.01
4.	z=2cos(xπ)+sin(πx/2)	Deskret Fure	x (0; 9/π *N), Δx=0.01
5.	z=3cos(x/π)-2sin(x/2π)	Deskret Cosinus	x (0; 8/π *N), Δx=0.01
6.	z=5cos(x2/π)-2sin(πx/2)	Deskret Cosinus	x (0; 8/π *N), Δx=0.01
7.	z=cos(x2/π)-sin(πx/4)	Deskret Fure	x (0; 7/π *N), Δx=0.01
8.	z=cos(2x)+2sin(πx/3)	Deskret Cosinus	x (0; 7/π *N Δx=0.01
9.	z=cos(x/3π)+2sin(πx/5)	Deskret Fure	x (0; 6/π *N), Δx=0.01
10.	z=cos(xπ)+2sin(x/2)	Deskret Fure	x (0; 6/π *N), Δx=0.01
11.	z=2cos(x*1/2)+sin(πx/2)	Deskret Cosinus	x (0; 5/π *N), Δx=0.01
12.	z=3cos(x2/π)-2sin(xπ)	Deskret Cosinus	x (0; 5/π *N), Δx=0.01
13.	z=5cos(x-2/π)-2sin(πx/2)	Deskret Fure	x (0; 4/π *N), Δx=0.01
14.	z=cos(xπ/2)-sin(xπ/3)	Deskret Cosinus	x (0; 4/π *N), Δx=0.01
15.	z=cos(2+x/π) +2sin(x)	Deskret Fure	x (0; 3/π *N), Δx=0.01
16.	z=cos(xπ)+2sin(xπ/5)	Deskret Fure	x (0; 3/π *N), Δx=0.01
17.	z=cos(x/π)+2sin(xπ)	Deskret Cosinus	x (0; 2.5/π *N), Δx=0.01
18.	z=cos(x+2/π)+2sin(2xπ)	Deskret Cosinus	x (0; 2.5/π *N), Δx=0.01
19.	z=cos(x/π6)+2sin(x3π)	Deskret Fure	x (0; 2/π *N), Δx=0.01
20.	z=2cos(x/π)+sin(x)	Deskret Cosinus	x (0; 2/π *N), Δx=0.01
21.	z=3cos(2x/π)-sin(πx)	Deskret Cosinus	x (0; 1.5/π *N), Δx=0.01

Namuna

Deskret cosinus o‘zgartirish algoritmi uchun

Deskret Fure o‘zgartirish algoritmi uchun

Xulosa: ishning yakunida xulosa yoziladi.

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