“PEDAGOGS”
international research journal ISSN:
2181-4027
_SJIF:
4.995
www.pedagoglar.uz
Volume-27, Issue-1, February - 2023
56
a=26 sm
b=a-11=26-11=15 sm; d=a+4=26+4=30 sm.
Javob:
Uchburchakning tomonlari
a=26 sm, b=15 sm
va
d=30 sm
ga teng.
3-masala:
Berilganlardan
foydalanib, geometrik
shakllarning perimetri va
yuzasini topishning formulalarini yarating.
Chizma:
Yechish:
To‘g‘ri to‘rtburchakning
yuzasi
S=a∙b
va
perimetri
P=2∙(a+b)
formulalari orqali topilishini bilgan holda berilganlardan
foydalanib formulalarni
yaratamiz.
P=2∙(A+B)+2∙(M+N)=2∙(A+B+M+N)
S=A∙B-M∙(A-2C)-N∙(A-2D)
Javob:
To‘g‘ri to‘rtburchakning yuzasi
S=A∙B-M∙(A-2C)-N∙(A-2D)
hamda
perimetri
P=2∙(A+B+M+N)
formulalariga teng.
4-masala:
Geometrik shaklning yuzini toping: Berilgan 7 ta shaklning 4- va 5-
laridan boshqa hammasi kvadratdan iborat va 6-, 7-shakllar bir-biriga teng. S
1
=100
см
2
, S
2
=4 sm
2
, S
3
=64 sm
2
ga teng bo‘lsa, berilgan barcha shakllarning perimetrini va
4-, 5-, 6- va 7-shakllarning yuzasini toping. Umumiy shaklning
yuzi va perimetrini
ham toping.
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