MAX-NORM STABILITY OF LOW ORDER TAYLOR-HOOD ELEMENTS
IN THREE DIMENSIONS
23
Finally, using the same arguments we prove the assumption A6.
Lemma 5.2. Assume that every mesh element has at least 3 edges in int(Ω). There exists a
constant c > 0 independent of h such that
sup
v∈V
h
\{0}
(q,
· v)
v
W
1
∞
(Ω)
≥ ch
q
L
1
(Ω)
,
∀q ∈ M
h
.
Proof. Similarly to the previous proof we define the number of internal edges N
i
ed
. For edge i,
with 1 ≤ i ≤ N
i
ed
denote by d
i
, f
i
and m
i
as before. Define v ∈ V
h
for q ∈ M
h
and for all T ∈ T
h
as follows
v = 0,
at the vertices of T
v(m
i
) = −l
i
τ
i
sgn(∂
τ
i
q),
for all the interior edges i of T
Then, it is clear that v ∈ V
h
and
Ω
q
· vdx = −
Ω
v ·
qdx
=
−
T ∈T
h
T
v ·
qdx
=
−
T ∈T
h
m∈T
v(m) ·
q(m)
5
−
n∈T
v(n) ·
q(n)
20
|T |
=
−
T ∈T
h
m
i
∈T
v(m
i
) ·
q(m
i
)
5
|T |
=
T ∈T
h
m
i
∈T
|∂
τ
i
q|l
i
|T |
5
≥ c
T ∈T
h
h
T
q
L
1
(T )
.
Recalling again that the inequality | q · τ
i
| ≤ | q| is possible thanks to that every element has
at least 3 internal edges. Furthermore, using the definition of v and its local shape function
representation we have
v
W
∞
1
(Ω)
≤ Ch
−1
max
T ∈T
h
max
m
i
∈T
|v(m
i
)| ≤ C.
This completes the proof.
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