ANSwER ExPlANATIONS
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SAT Practice Test #8
Choice A is incorrect. The expression 1
_
x + 1 is not equivalent to
f(
x)
_
g(
x)
because at
x = 0, 1
_
x + 1 as a value of 1 and
f(
x)
_
g(
x) has a value of 0.
Choice B is incorrect and results from omitting the factor
x in the
factorization of
f (
x). Choice C is incorrect and may result from
incorrectly factoring
g (
x) as (
x + 1)(
x + 3) instead of (
x +1)(
x – 3).
QUESTION 9
Choice A is correct. The standard form for
the equation of a circle is
(
x –
h)
2
+ (
y –
k)
2
=
r
2
, where (
h,
k) are the coordinates of the center
and
r is the length of the radius. According to the given equation, the
center of the circle is (6, –5). Let (
x
1
,
y
1
) represent
the coordinates of
point
Q.
Since point P (10, –5) and point
Q (
x
1
,
y
1
) are the endpoints
of a diameter of the circle, the center (6, –5)
lies on the diameter,
halfway between
P and
Q. Therefore, the following relationships hold:
x
1
+ 10
_
2 = 6 and
y
1
+ (−5)
_
2
= −5. Solving the equations for
x
1
and
y
1
,
respectively, yields
x
1
= 2 and
y
1
= −5. Therefore, the coordinates of
point
Q are (2, –5).
Alternate approach: Since point
P (10, −5) on the circle and the center
of the circle (6, −5) have the same
y-coordinate, it follows that the
radius of the circle is 10 – 6 = 4.
In addition, the opposite end of the
diameter
_
PQ must have the same
y-coordinate as
P and be 4 units away
from the center. Hence,
the coordinates of point Q must be (2, –5).
Choices B and D are incorrect because the points given in these
choices lie on a diameter that is perpendicular to the diameter
_
PQ . If
either of these points were point
Q, then
_
PQ would
not be the diameter
of the circle. Choice C is incorrect because (6, −5) is the center of the
circle and does not lie on the circle.
QUESTION 10
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