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DNK MASALA JAVOBI BILAN(2)
D)300
Ishlanishi:
1) 2T+3G=5G 2T=2G T=G
2T+2G=240 2T+2T=240 4T=240 T=60
2) H=5T H=5*60 H=
300 Javob: D
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143. Bir DNK da 750 ta, 2-DNK da 1100ta nukleotid bo`lsa, 1-
DNK dagi purin asosi G lar sonidan 2,5 marta ko`p, 2-DNKdagi
adeninlar soni pirimidin sonidan 2,75 marta kam bo`lsa, 2ta
DNKdagi vodorod bog`lar ayirmasini aniqlang.
A)550
B)450 C)350 D250
Ishlanishi:
1)
1-DNK da H bog’larni topamiz:
2A+2G=750 A+G=2,5G A=1,5G
2) 2*1,5G+2G=750 5G=750
G=150
3) 2A+2*150=750 2A=750-300 2A=450
A=225
4) H=(2*225)+(3*150) H=450+450
H
1
=900
5) 2A+2G=1100
S+T=2,75A S=G T=A A+G=2,75A G=1,75A
6) 2A+2*1,75A=1100 5,5A=1100
A=200
7) 2*200+2G=1100 2G=1100-400 2G=700
G=350
8) H=(2*200)+(3*350) H=400+1050
H
2
=1450
9) x=H
1
-H
2
x=1450-900=
550 Javob: A
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144. (A+T)-(G-S)=30 va umumiy vodorod bog`lar soni 360
bo`lsa, DNK fragmenti uzunligini aniqlang.(qo`shni nukleotidlar
orasidagi masofa 0,34nm)
A)49,98
B)50,4 C)61,2 D)45
Ishlanishi:
1) 2A+3G=360
2A-2G=30 5G=330
G=66
2) 2A+3*66=360 2A=360-198 2A=162
A=81
3) 66+81=147 -bu 1 ta zanjirdagi N lar
L=N*0,34 L=147*0,34 L=
49,98 Javob: A
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145. (A+T)-(G-S)=60 va umumiy vodorod bog`lar soni 300
bo`lsa, DNK fragmenti uzunligini aniqlang.(qo`shni nukleotidlar
orasidagi masofa 0,34nm)
A)51
B)50,4 C)61,2 D)45
Ishlanishi:
1) 2A+3G=360
2A-2G=60 5G=300
G=60
2) 2A+3*60=360 2A=360-180 2A=180
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