1 =900 5) 2A+2G=1100
S+T=2,75A S=G T=A A+G=2,75A G=1,75A
6) 2A+2*1,75A=1100 5,5A=1100 A=200 7) 2*200+2G=1100 2G=1100-400 2G=700 G=350 8) H=(2*200)+(3*350) H=400+1050 H 2 =1450 9) x=H
1
-H
2
x=1450-900=550 Javob: A ____________________________
144. (A+T)-(G-S)=30 va umumiy vodorod bog`lar soni 360
bo`lsa, DNK fragmenti uzunligini aniqlang.(qo`shni nukleotidlar
orasidagi masofa 0,34nm)
A)49,98 B)50,4 C)61,2 D)45
Ishlanishi: 1) 2A+3G=360
2A-2G=30 5G=330 G=66 2) 2A+3*66=360 2A=360-198 2A=162 A=81 3) 66+81=147 -bu 1 ta zanjirdagi N lar
L=N*0,34 L=147*0,34 L=49,98 Javob: A ____________________________
145. (A+T)-(G-S)=60 va umumiy vodorod bog`lar soni 300
bo`lsa, DNK fragmenti uzunligini aniqlang.(qo`shni nukleotidlar
orasidagi masofa 0,34nm)
A)51 B)50,4 C)61,2 D)45
Ishlanishi: 1) 2A+3G=360
2A-2G=60 5G=300 G=60 2) 2A+3*60=360 2A=360-180 2A=180 A=90 3) 90+60=150 -bu 1 ta zanjirdagi N lar
L=N*0,34 L=150*0,34 L=51 Javob: A ____________________________
146. (A+T)-(G-S)=50 va umumiy vodorod bog`lar soni 300
bo`lsa, DNK fragmenti uzunligini aniqlang.(qo`shni nukleotidlar
orasidagi masofa 0,34nm)
A)42,5 B)50,4 C)61,2 D)45
Ishlanishi: 1) 2A+3G=300
2A-2G=50 5G=250 G=50 2) 2A+3*50=300 2A=300-150 2A=150 A=75 3) 75+50=125 -bu 1 ta zanjirdagi N lar
L=N*0,34 L=125*0,34 L=42,5 Javob: A ____________________________
147. (A+T)-(G-S)=50 va umumiy vodorod bog`lar soni 425
bo`lsa, DNK fragmenti uzunligini aniqlang.(qo`shni nukleotidlar
orasidagi masofa 0,34nm)
A)59,5 B)50,4 C)61,2 D)45