Agar geometrik progressiyada: 4 bo`lsa, uning maxraji toping

Mashqlar.
58. Agar geometrik progresssiyada:
1)
6)
bo`lsa, uning dastlabki n ta hadini yig`indisini toping.
59. Geometrik progressiya dastlabki yettita hadining yig`indisini toping:
1) 5, 10, 20, … 2) 2, 6, 18, …
60. Agar geometric progressiyada: 1) =2, bo`lsa, va ni toping;
2) bo`lsa, va ni toping.
61. Agar geometric progressiyada:
1) 2)
3) 4)
bo`lsa, uning hadlari soni n ni toping.
62. Agar geometrik progressiyada:
1) bo`lsa, n va ; 2) bo`lsa, n va ;
3) bo`lsa, n va ; 4) bo`lsa, n va
toping.
63. Agar sonlar yig`indisining qo`shiluvchilari geometric progressiyaning ketma-ket hadlari bo`sa,
shu progressiyani toping.
1) 1+2+4+…+128; 2) 1+3+9+…+243; 3) -1+2-4+…+128: 4) 5-15+45-…+405.
64. Agar geometric progressiyada:
1) bo`lsa, va ni toping.
65. Geometrik progressiya n-hadining formulasi bilan berilgan:
1) bo`lsa, ni toping; 2) bo`lsa, ni toping.
66. Ayniyatni isbotlang: bunda n daraja ko`rsatkichi va
u birdan katta natural son.
67. Geometrik progressiyada:
1) bo`lsa, va ni toping; 2) bo`lsa, va ni toping.
68. Geometrik progressiyada:
1) va bo`lsa, ni toping;
2) va bo`lsa, ni toping;
3) va bo`lsa, ni toping;
4) va bo`lsa, ni toping.

CHEKSIZ KAMAYUVCHI GEOMETRIK PROGRESSIYA.

Maxrajning moduli birdan kichik bo`lgan geometrik progressiya cheksiz kamayuvchi geometrik progressiya deyiladi.