C# dasturlash tilida fayllar bilan ishlash

1- misol. uqish.txt fayldan ikkita sonni o’qib, ularni yig’indisini yozish.txt fayliga yozish dasturini ko’rib chiqamiz.
using System;

using System.Collections.Generic; using System.Linq;

using System.Text; using System.IO;
namespace ConsoleApplication1

{

class Program

{

static void Main(string[] args)

{

StreamWriter yozish = new StreamWriter("d:\\yozish.txt");
StreamReader uqish = new StreamReader("d:\\uqish.txt"); yozish.WriteLine(int.Parse(uqish.ReadLine()) + int.Parse(uqish.ReadLine()));
yozish.Close(); uqish.Close();
} } }

Dastur natijasi: dasturni ishlatishdan oldin uqish.txt faylda 2 ta son kiritish kerak, so’ng dastur ikkita sonni o’qib, ularni yig’indisini yozish.txt fayliga yozadi. Natijani ko’rish uchun yozish.txt faylni ochib ko’rish kerak

2-misol. fayl davomidan ma’lumotlarni yozish. class Program
{

static void Main(string[] args)

{

/*textFile.txt faylining yangi satridan "yangi satr" so'zini qo'shadi agar bu fayl bo'lmasa o'zi yaratib "yangi satr" so'zini qo'shadi*/ StreamWriter a;
a = File.AppendText("d:\\textFile.txt"); a.WriteLine("yangi satr");
a.Close();

} }
3- misol. fayldan ma’lumotlarni bitta bitta belgi orqali oqish va chiqarish. class Program

{

[STAThread]

static void Main(string[] args)

{

StreamReader uqish; try{
uqish = new StreamReader("d:\\textFile.txt");

}

catch {

Console.WriteLine("Faylni ochishda xatolik bor"); Console.ReadKey();

return;

}

int ch;

while ((ch = uqish.Read()) != (-1))

{

Console.WriteLine((char)ch);

}
Console.ReadKey();

} }