A) 40 % B) 18,5 % C) 17,5 %D) 25 %
Ishlanishi: 1) G-400=400-S ikkalasi 800 tani tashkil etadi.
2) 6400-800=5600 Demak, 5600 G va S ni tashkil etishi kerak
va ular: 5600/2=2800 G-2800=2800-S ni tashkil qiladi
3) S dan foydalanib, A ning umumiy miqdorini topamiz:
2800 --- 100%
x --- 40% x=(400*40)/100=2800 T=A=1120
4) 6400 --- 100%
(A)1120 --- x% x=(1120*100)/6400=17,5% Javob: C ____________________________
55. UASASAGSUSUG ushbu i-RNK sintezlangan DNK
molekulasi necha vodorod bog’ orqali hosil bo’lgan
A) 25 ta B) 31 ta C) 50 ta D) 72
Ishlanishi: 1) RNK dagi zanjir - UASASAGSUSUG DNK dagi 1-zanjir - ATGTGTSGAGAS DNK dagi 2-zanjir - TASASAGSTSTG 2) A-T lar jami 5 ta, G-S lar jami 7 ta H=(6*2)+(6*3)=30 J:C ____________________________
56. Muayyan DNK bo’lagini 1-ipida AAGSGTAGT nukleotidlar
qatori bor. Shu DNK ning 2-ipidan sintezlangan RNK dagi
nukleotidlar qatorini toping.
A) AAGSGUAGU B) AAGSGUAGUC
C) GSUUSGTTSU
D) AAGSGTUAGU
Ishlanishi: 1) DNK dagi 1-zanjir - AAGSGTAGT
DNK dagi 2-zanjir - T T SGSAT SA 2) i-RNK dagi zanjir - AAGSGUAGU Javob: A ____________________________
57. DNK molekulasini ikki ipida 6400 ta nukleotid bor. Umumiy
nukleoitlarni 25 % i adenin. 1-ipda timin nukleotidini 70 % i,
guaninlarni esa 30 % joylashgan. DNK molekulasida nechta
vodorod bog’ mavjud
A) 800 B) 8000 C) 1600 D) 16000
Ishlanishi: 1) 6400-100%
x--- 25% x=(6400*25)/100=1600
A=25% bo’lgani uchun T-G-S lar ham 25% dan bo’ladi, ya’ni
A=T=G=S=A-1600
2) H=2A+3G H=(2*1600)+(3*1600)=3200+4800=8000 J: B ____________________________
58. Timin uchramaydigan nuklein kislota tarkibida 43 ta A, 23 ta
G, 65 ta S, va 90 ta U bor. Shu molekula sintezlangan DNK dagi
nukleotidlar sonini toping?
A) 884 B) 442 C) 221 D) 1768
