12–Ma’ruza. Timsollarni o’rganuvchi va tanuvchi tizimlar

x1	x2	x3	x4	x5	x6	x7	x8	x9	x10	x11	x12	x13	x14	x15
X1	1	1	1	0	0	1	1	0	1	0	1	0	1	1	1	V1
X2	0	1	1	0	0	1	0	1	1	0	1	0	0	1	0
X3	1	0	1	1	1	0	0	1	1	1	0	1	1	1	0
X4	0	0	1	0	0	0	1	0	1	1	1	0	1	0	1	V2
X5	0	1	1	1	0	1	0	0	1	0	0	0	1	1	1
X6	1	0	0	1	0	0	1	0	0	1	1	0	0	0	0
X7	1	0	0	1	1	0	0	1	1	1	0	0	0	1	0	V3
X8	1	0	0	1	1	0	1	0	0	1	1	1	1	0	1
X9	1	1	1	1	0	1	0	0	1	1	1	0	0	1	0
X10	0	0	1	1	0	0	0	0	0	0	0	0	0	0	0	V4
X11	1	0	0	0	1	0	1	0	1	1	0	1	1	0	0
X12	1	0	1	1	1	0	1	1	1	1	1	1	1	1	0
X*	1	0	1	0	1	0	1	0	1	0	1	1	0	1	1

Talab etiladi: tanlovdanhar bir sinf uchun oddiy BTni topish va ular yordamida X* yangi timsolning qaysi sinfga tegishli ekanligini aniqlash.
Masalaning yechilishi. tanlovdan sinflar uchun oddiy BT topiladi (12.6-12.9 jadvallar).
Natija. sinf uchun 1- tipli , sinf uchun 2-tipli , sinf uchun 1- tipli va sinf uchun 2-tipli HQQlarni hosil qilamiz.
Hosil qilingan qoidalar yordamida yangi X* timsolning qaysi sinfga tegishli ekanligini aniqlaymiz:
sinfga xos ;
sinfga xos ;
sinfga xos ;
sinfga xos .

12.6-jadval 12.7-jadval

	x3	x9	x14					x5	x8	x12
X1	1	1	1	1	V1		X1	0	0	0	0
X2	1	1	1	1			X2	0	1	0	1
X3	1	1	1	1			X3	1	1	1	1
X4	1	1	0	0			X4	0	0	0	0	V2
X5	1	1	1	1			X5	0	0	0	0
X6	0	0	0	0			X6	0	0	0	0
X7	0	1	1	0			X7	1	1	0	1
X8	0	0	0	0			X8	1	0	1	1
X9	1	1	1	1			X9	0	0	0	0
X10	1	0	0	0			X10	0	0	0	0
X11	0	1	0	0			X11	1	0	1	1
X12	1	1	1	1			X12	1	1	1	1
X*	1	1	1	1			X*	1	0	1	1

12.8-jadval 12.9-jadval

	x1	x4	x10					x2	x6	x15
X1	1	0	0	0			X1	1	1	1	1
X2	0	0	0	0			X2	1	1	0	1
X3	1	1	1	1			X3	0	0	0	0
X4	0	0	1	0			X4	0	0	1	1
X5	0	1	0	0			X5	1	1	1	1
X6	1	1	1	1			X6	0	0	0	0
X7	1	1	1	1	V3		X7	0	0	0	0
X8	1	1	1	1			X8	0	0	1	1
X9	1	1	1	1			X9	1	1	0	1
X10	0	0	1	0			X10	0	0	0	0