1. Matematik mayatnikning tebranish amplitudasi A ga, maksimal
tezlanishni a ga teng bo‘lsa, uning uzunligini aniqlang.
A)Aga B)Ag/a C)ag/A D)Ag/a
2
2. Kichik jism l uzunlikdagi ipga osilgan holda A amplituda bilan
tebranmoqda. Jismning maksimal tezligini toping.
A)
g
A
2
l
B)
g
A
l
C) l
g
A
D)
l
g
A
2
3. m massali sharcha l uzunlikdagi ipga osilgan holda A amplituda
bilan tebranmoqda. Sharchaning maksimal kinetik energiyasini
toping.
A)A
2
mg/(2l) B)A
2
mg/l C)A
2
2l/(mg) D)Amg/l
4. 0,2 kg massaga ega bo‘lgan yuk bikrligi 500 N/m bo‘lgan
prujinaga osilgan holda tebranmoqda. Agar tebranish amplitudasi 4
cm bo‘lsa, yukning maksimal tezligi qanchaga teng (m/s)?
A)1 B)2 C)8 D)4
5. Garmonik tebranayotgan nuqta tezligi vaqtga bog‘liq ravishda
qanday o‘zgaradi?
A)sinus yoki kosinus qonuni bo‘yicha o‘zgaradi
B)vaqtga to‘g‘ri proporsional o‘zgaradi
C)vaqtga teskari proporsional o‘zgaradi
D)o‘zgarmas saqlanadi
6. Berilgan tenglamalar orasidagi garmonik tebranishni
harakterlovchi ifodalarni toping. 1)x=Asin(ωt+α);
2)
;
2
at
t
x
x
2
o
o
+
u
+
=
3)x=Acos(ωt+α); 4)x=F/k; 5)x=x
o
+υt
A)1; 3 B)2; 4 C)2; 3; 5 D)1; 2; 4
7. Tebranayotgan jism tezligining tenglamasi υ=2sin(3t+π/3) m/s
ko‘rinishda bo‘lsa, tebranish tezligining boshlang‘ich fazasi nimaga
teng bo‘ladi?
A)3t+π/3 B)3t C)π/3 D)0
8. OX o‘qi bo‘ylab yuk tebranishi x=6cos(2t+π/2) tenglama bilan
ifodalansa, 3 s vaqtdagi tebranish fazasi berilgan javoblardan
topilsin.
A)6+π/2 B)3 C)6 D)π/2
9. 1 daqiqa ichida 60 ta tebranadigan, amplitudasi 8 cm ga teng va
boshlang‘ich fazasi 3π/2 rad bo‘lgan garmonik tebranishning
tenglamasini toping.
A)x=0,08cos(2πt+3π/2) B)x=0,08cos(2πt+3t/2)
C)x=0,08cos(πt+3π/2) D)x=0,08cos(πt+3t/2)
10. Moddiy nuqtaning harakat tenglamasi x=sinπt (m) bo‘lsa, uning
tezlik amplitudasi nimaga teng (m/s)?
A)1,57 B)0,5 C)3,14 D)6,28
11. Matematik mayatnikning uzunligi 1 m, tebranish amplitudasi 5
cm bo‘lsa, sanoq boshi qilib muvozanat vaziyatini tanlab olib
harakat tenglamasini tuzing.
A)
t
10
sin
5
x
=
B)
t
10
sin
5
,
0
x
=
C) t
10
sin
05
,
0
x
=
D)
t
10
sin
005
,
0
x
=
12. Yukining massasi 0,05 kg bo‘lgan prujinali mayatnikning
tebranish qonuni x=0,05sin10t (m) ko‘rinishga ega. Prujinaning
bikrligini toping (N/m).
A)1,6 B) C)5 D)6,4
13. Mexanik tebranishlar x=0,3cos(16πt+π/2) qonuniyat bo‘yicha
ro‘y berayotgan bo‘lsa, tebranishlar davrini toping (s).
A)16 B)8 C)1/16 D)1/8
14. Tebranishlar x=5sin(2πt+0,5π) qonuniyat bo‘yicha ro‘y
berayotgan bo‘lsa, tebranishlar chastotasini toping (Hz).
A)5 B)2 C)1 D)0,5
15. Matematik mayatnikning tebranish qonuni x=0,1sin(10πt+π)
ko‘rinishga ega. Tezlikning amplitudaviy qiymatini toping (m/s).
A)0,1 B)20 C)1 D)π