O‘zbekiston respublikasi

abs Q = Q_erish (modda)_nazariy - Q_erish(modda)_tajriba.

nisbiy Q = Q / Q _nazariy  100 %

Tajriba- 2 natijalarini hisoblash

Eritmaning umumiy hajmini hisoblang:

V(er-ma) =V (_ishqor) + V _(kislota)
Kuzatilgan issiqlik effektini hisoblang:
Q_(Kuzat) = sV(_Eritma) r  t
Bu erda: eritma zichligi - r=1g/ml ; t°=t₂ – t₁; s = 4,2 J/ggrad.

4. Proporsiyadan foydalanib berilgan hajmdagi ishqorni miqdorini toping

1000 ml eritmada 1 mol NaOH, chunki S=1M

Vml n mol NaOH, n=V/1000=V  10^-3 (mol)

Berilgan proporsiyadan foydalanib neytrallanish reaksiyaning issiqlik effektini hisoblang:

nmol Q_(kuzat)

1 mol Q _{(neytrallanish)}

5. Q_(nazariy) = + 57,54 J/mol qilib olib tajribani

absolyut va nisbiy xatosini toping

abs Q = Q(neytrallanish)_nazariy- Q(neytrallanish)_tajriba.

nisbiy Q =Q / Q_nazariy 100 %
4-laboratoriya ishini

HISOBOTI
Quyidagi tushunchalarni izohlang:

Uskuna sxemasi

1. Endotermik jarayon ______________________________________

bunda reaksiyani N° ______________________________________

2. Ekzotermik jarayon ______________________________________

bunda reaksiya H° ______________________________________

Standart sharoitlar : T= ______________________________________

R= ___________________________. s= __________________

3. Murakkab moddaning hosil bo‘lish issiqligi (H°₂₉₈)______________

_______________________________________________________

4. Modda erish issiqlik effekti_________________________________

_________________________________________________________

5. Neytrallanish reaksiyani issiqlik effekti ______________________

6. 
   Gess qonuni va uning matematik ifodasi: ______________________
   

6. 
   Gess qonunidan kelib chiqadigan xulosa va uni
   

matematik ifodasi ________________________________________

________________________________________________________