5-1 izoxora orqali:
(196)
T4
E
k-1
Т5 = Г 1ек- 1 Х р ^ т ;
T5 = T y X pk
e
( 1 9 7 )
Shu q iy m a tla m i FIK ifo d asig a q u y ish b ila n
q u y id a g in i hosil
qilam iz.
O x irgi ifo d a d a n k o 'rin ib
tu rib d ik i,
sik ln in g FIK
к,
e,
X,
p lar-
n in g o 'z g a ris h i b ila n o 'z g a ra d i.
P o rsh en li ichki y o n u v d v ig ate li z?=const d a y o q ilg 'in i
y o n ish
sikli b o 'y ic h a ishlaydi. S hu siklni h a r b ir n u q ta s id a g i p a ra m e trla ri
ni, o lin g a n ishni, k e ltirilg a n va olib k e tilg a n
issiqlikni te rm ik FIK-
n i
an iq lan g , a g a r Pi = 1 b a r, f = 20 °C, £ = 3,6; Л = 3,33;
к =
1,4 bo'Isa.
Ishchi jism - h avo. Issiq lik sig 'im i o 'z g a rm a s d e b h iso blansin.
Y echish. H iso b la sh n i 1 k g h a v o u c h u n olib b o ram iz:
M asala.
1-nuqta:
?! = 1 bar,
t
= 200 °C
h o la t te n g la m a s id a n
= RT^
2-nuqta:
A d ia b a tik to ra y ish d a g i h a ro ra t
T 2 = T j ( - ^ - ) k " 1 = 2 9 3 3 , 6 0 ' 4 = 4 8 9 К
v
2
t2=216 °C
100
n
RT
2
287 489
P7 = — - = ---------- = 6,02 bar
2
v
2
0,233
3-nuqta:
y3= У
2
= 0,233 m 3/kg
Izo x o r ja ra y o n d a p a ra m e trla r o ra s id a g i b u g 'la n is h g a
lanib:
5 - = ^ - = X = 3,33
P2
^2
P3= P2A = 6,02 • 3,33 = 20 bar.
T3= Т2Л = 489 • 3,33 = 1628 К, f3 = 1355 °C
4-nuqta:
P3= Р2Л = 6,02 • 3,33 = 20 bar.
T3= Т2Л - 489 • 3,33 = 1628 K, t3 = 1355 °C
5-nuqta:
v A= Vi =
0,84 m 3/kg.
т4 = Г з А * - 1 =
Т з А 1"1
=
1 6 2 8
- A
= 976 К
У
4
Dl
3,6 '
P = P
1 1
= 1 ^ = 3 , 3 3
bar
4
1 T!
293
, =
cv(T3- T2) =
(20,93/28,96)(l 628 - 489) = 825 kj/kg
<]2
= cv(T
4-T O = (20,93/28,96)(976 - 293) = 495 kj/kg
T e rm ik FIK
q, = (825 - 495)/825 = 0,4 = 40 %
n ,= 1 - ^ = 1 - ^ = 0,4 = 40%
Sikl ishi:
*0 = f t - <72 = 330 kj/kg
asos-
72>
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