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səhifə | 8/10 | tarix | 10.11.2022 | ölçüsü | 0,96 Mb. | | #68465 |
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- > restart; > with(student): > IT12:=changevar(tan(x)=t,int(tan(x)^5,x),t); > IT12:=changevar(t=tan(x), (IT12, t),x); 10-misol.
- > restart; > with(student): > IT13:=changevar(2+3*sin(2*x)=t, int(cos(2*x)/(2+3*sin(2*x))^(2/3),x),t);
- > restart; > IT5m:=Int(sin(x)^3*cos(x)^4,x)=int(sin(x)^3*cos(x)^4,x);
> restart;
> with(student):
> IT10:=changevar(tan(x)=t,Int(tan(x)^3,x),t);
> IT10:=value(%);
> IT10:=changevar(t=tan(x), (IT10, t),x);
2) Bevosita integrallash.
> restart;
> Int(tan(x)^3,x)=int(tan(x)^3,x);
9-misol. tgx=t almashtirish yordamida integralni topish
> restart;
> with(student):
> IT12:=changevar(tan(x)=t,int(tan(x)^5,x),t);
> IT12:=changevar(t=tan(x), (IT12, t),x);
10-misol. bu integralni topishda yuqoridagilardan farqli quyidagicha almashtrish qilamiz:
Bu holda
=
1) o`zgaruvchini almashtirish yordamida integralni topish.
> restart;
> with(student):
> IT13:=changevar(2+3*sin(2*x)=t,
int(cos(2*x)/(2+3*sin(2*x))^(2/3),x),t);
> IT13:=changevar(t=2+3*sin(2*x), (IT13, t),x);
2) Bevosita integrallash.
> restart;
> Int(cos(2*x)/(2+3*sin(2*x))^(2/3),x)=
int(cos(2*x)/(2+3*sin(2*x))^(2/3),x);
3. Sinus va kosinus toq darajali bo`ganda integrallash
a)
bu yerda t=cosx.
b)
bu yerda t=sinx.
> restart;
> IT3m:=Int(sin(x)^(2*m+1),x)=int(sin(x)^(2*m+1),x);
> m:=1:IT3m;
> m:=2:IT3m;
11-misol.. integralni hisoblang.
YEchish. va ekanligini hamda
almashtirish kiritib, quyidagini hosil hilamiz:
> restart;
> IT5m:=Int(sin(x)^3*cos(x)^4,x)=int(sin(x)^3*cos(x)^4,x);
Dostları ilə paylaş: |
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